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Question

In the question, a pair of equations is given. Find the values of a and b and choose the appropriate condition

I. 3a + 2b = 14

II. a + 4b = 13


A

if a < b

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B

if a ≤ b

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C

if a = b

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D

if a > b

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E

if a ≥ b

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Solution

The correct option is D

if a > b


I. 3a + 2b = 14

II. a + 4b = 13

Subtract equation I from equation II after multiplying II by 3.

We get 3a + 12b - 3a - 2b = 39 - 14

10b = 25

b = 2.5

Put value of b in equation II.

We set a + 4 × 2.5 = 13.

Therefore, a = 3. Thus, a > b.


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