In the question, a pair of equations is given. You have to find out the values of x and y and choose the appropriate answer.
I. 4x2 - 4x - 3 = 0
II. 4y2 + 12y + 5 = 0
if x < y
if x y
if x > y
4x2−4x−3=0⇒x=32,12,4y2+12y+5=0⇒y2=−12,−52∴x≥y
I.4x2−4x−3=0
II.4y2+12y+5=0
In the following question, two equations numbered I and II are given. Find the values of x and y and choose the appropriate answer.
I. 3x2 + 8x + 4 = 0
II. 4y2 - 19y + 12 = 0