In the question, a pair of equations is given. You have to find out the values of x and y and choose the appropriate answer.

$I . 4 x^{2} - 4 x - 3 = 0$

$I I .4 y^{2} + 12 y + 5 = 0$

if x < y

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if x y

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if x = y

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if x > y

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if x y

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Solution

The correct option is E
if x y

$\begin{matrix} 4 x^{2} - 4 x - 3 = 0 \Rightarrow x = \frac{3}{2}, \frac{1}{2}, 4 y^{2} + 12 y + 5 = 0 \Rightarrow y^{2} = - \frac{1}{2}, - \frac{5}{2} ∴ x \geq y \end{matrix}$

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Similar questions

In the question, a pair of equations is given. You have to find out the values of x and y and choose the appropriate answer.

I. ${4 x}^{2}$ - 4x - 3 = 0

II. ${4 y}^{2}$ + 12y + 5 = 0

4 x^{2} - 4 x - 3 = 0

4 y^{2} + 12 y + 5 = 0

4 x^{2} = 25

2 y^{2} - 13 y + 21 = 0

4 x^{2} - 41 x + 105 = 0

20 y^{2} + 101 y - 21 = 0

4 x^{2} + 2 x - 30 = 0

3 y^{2} + 33 y + 72 = 0

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