Question

Question 38

In the question given below, fill in the blank to make the statement true:

$a^2-b^2=(a+b)$ ___

Answer 1

$(a-b)$

We have , $a^2-b^2=(a+b)(a-b)$
$[\because (a+b\left)\right(a-b)=a^2-ab+ba-b^2=a^2-b^2]$

Alternative Method :
$Let(a^2-b^2)=(a+b)x\Rightarrow x=\frac{a^2-b^2}{a+b}=\frac{(a+b)(a-b)}{a+b}=a-b$