Question

In the questions below, 2 equations are given. Solve both the equation and choose the correct option. (SBI PO)
I. 2x${}^2$ - 8x + 6 = 0
II. 2y${}^2$ - 26y + 80 = 0

• A.
  x > y
• B.
  x $\ge$ y
• C.
  x < y
• D. x $\le$ y
• E. x = y or cannot be determined.

Answer 1

The correct option is C

x < y
2x${}^2$ - 8x + 6 = 0 $\Rightarrow$ x${}^2$ - 4x + 3 =0
(x -1) (x - 3) = 0
x = 1 or 3
y${}^2$ - 13y + 40 = 0
(y -5) (y - 8) = 0
y = 5 or 8
Largest value of x =3 < 5 = Least value of y
So, x < y