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Question

In the radioactive transformation
AZXAZ+1X1A4Z1X2A4ZX3
Which are the successively emitted radiactive radiation?

A
β,α,β
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B
β,β,α
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C
α,β,β
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D
α,α,β
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Solution

The correct option is C β,α,β
AZXAZ+1X1+x
In this equation, we will apply the law of conservation of mass number and conservation of atomic number.
x01β
AXAZ+1X1+01βA4Z1X2+azyA=A4+aa=4Z+1=Z1+zz=2y42αA4Z1X2+42αA4ZX3+bz1ZA4+b=A4b=0Z1=Z+z1z1=1Z01β

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