Question

In the reaction,
2Al + 6HCl = 2Al^3+ + 6Cl^- + 3H2
(a) 11.2L H2 at STP is produced for every mole of HCl consumed.
(b) 6L HCl is consumed for every 3L H2 produced.
(c) 33.6L H2 is produced regardless of temperature and pressure for every mole Al that reacts.
(d) 67.2L H2 at STP is produced for every mole Al that reacts.

Answer 1

2Al + 6HCl = 2Al^3+ + 6Cl^- + 3H2
Ie in the above mentioned equation 6 HCl gives 3 h2.
similarly