In the reaction, 2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g)
A
22.4LH2(g) at STP is produced for every mole HCl(aq) consumed
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B
6LHCl(aq) is consumed for every 3LH2(g) produced
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C
33.6LH2(g) is produced regardless of temperature and pressure for every mole Al that reacts
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D
67.2LH2(g) at STP is produced for every mole Al that reacts
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Solution
The correct option is C33.6LH2(g) is produced regardless of temperature and pressure for every mole Al that reacts 2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g)
At STP, 6 moles of HCl produces 3 moles
or 3×22.4L of HCl ∴ 1 mole of HCl produces 3×22.46=11.2L of HCl
Again at STP, 2 moles of Al produces 3 moles or 3×22.4L of HCl
or 1 mole of Al produces 3×22.42=33.6L of HCl