In the reaction, 2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g) :
A
11.2 L of H2(g) at STP is produced for every mol of HCl (aq) consumed.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6 L of HCl (aq) is consumed for every 3 L of H2(g) produced.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
33.6 L of H2(g) is produced regardless of temperature and pressure for every mol of Al that reacts.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
67.2 L of H2(g) at STP is produced for every mole of Al that reacts.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A11.2 L of H2(g) at STP is produced for every mol of HCl (aq) consumed. As the reaction suggests that for 6 mol HCl , 3 mol of H2 gas is produced At STP 1 mol of every gas has 22.4 L so 1 mol ( 22.4 L) , will produce 3/6∗22.4=1/2∗22.4=11.2 L of H2 gas.