In the reaction 2CuSO4-4KI- Cu2I2-2K2SO4-I2- the equivalent weight of CuSO4 is- Mw-159-5g mol-1

The correct option is A Mw 2Cu^2++2e^ → Cu^⊕_2 Number of e^ tranfer per mol =2/2=1 Ew of CuSO_4 = #160;Mwn factor= Mw1 = Mw ...

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Byju's Answer

Standard XII

Chemistry

Types of Redox Reactions

In the reacti...

Question

In the reaction $2 C u S O_{4} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$ , the equivalent weight of $C u S O_{4}$ is:
$(M w = 159.5 g$ $m o l^{- 1})$

M w

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\frac{M w}{2}

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\frac{M w}{4}

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\frac{M w}{3}

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Solution

The correct option is A $M w$
$2 C u^{2 +} + 2 e^{-} \to C u_{2}^{⨁}$
Number of $e^{-}$ tranfer per mol $= \frac{2}{2} = 1$
$E w$ of $C u S O_{4} = \frac{M w}{n - f a c t o r} = \frac{M w}{1} = M w$

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In the reaction 2CuSO4+4KI→Cu2I2+2K2SO4+I2, the equivalent weight of CuSO4 is: (Mw=159.5g mol−1)

The correct option is A Mw2Cu2++2e−→Cu⨁2Number of e− tranfer per mol =22=1Ew of CuSO4=Mwn−factor=Mw1=Mw

In the reaction $2 C u S O_{4} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$ , the equivalent weight of $C u S O_{4}$ is:
$(M w = 159.5 g$ $m o l^{- 1})$

The correct option is A $M w$
$2 C u^{2 +} + 2 e^{-} \to C u_{2}^{⨁}$
Number of $e^{-}$ tranfer per mol $= \frac{2}{2} = 1$
$E w$ of $C u S O_{4} = \frac{M w}{n - f a c t o r} = \frac{M w}{1} = M w$