Question

In the reaction, $2KCl{O}_3\to 2KCl+2O_2$
What is the volume of oxygen released under NTP conditions when 36.75 g of $KCl{O}_3$ is heated ?

• A. 3.6 litres
• B. 7.2 litres
• C. 10 litres
• D. 1.8 litres

Answer 1

The correct option is C 10 litres

$n_{KCl{O}_3}=\frac{36.75}{122.55}=0.30$
$2moleKCl{O}_3\to 3mole{O}_2$
$0.30moleKCl{O}_3\to \frac{3}{2}\times 0.30O_2$
$=0.45mole$
$V=0.45\left(22.4L\right)$
= 10.08 L
= 10