In the reaction, $2 N a_{2} S_{2} O_{3} + I_{2} = N a_{2} S_{4} O_{6} + 2 N a I, I_{2}$ acts as.

Reducing agent

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Oxidising agent

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Oxidising as well as reducing agent

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None of the above

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Solution

The correct option is A Oxidising agent
$I_{2}$ acts as an oxidising agent as it get reduced from (0) oxidation state in $I_{2}$ to -1 oxidation state in $N a I$ .

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Similar questions

I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I

I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}

N a_{2} S_{2} O_{3}

2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I

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