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Byju's Answer

Standard IX

Chemistry

Preparation of Hydrogen from Cold Water and Metals

In the reacti...

Question

In the reaction $2 S O_{2} + O_{2} \to 2 S O_{3}$ , 0.25 mole of sulfur dioxide is mixed with 0.25 mole of oxygen and allowed to react. What is the maximum number of moles of $S O_{3}$ , that can be produced?

0.0625 moles

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0.125 moles

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0.25 moles

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0.5 moles

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1.0 mole

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Solution

The correct option is D 0.25 moles
Option C is the correct answer.
From the equation it is seen that,
2 moles of $S O_{2}$ react with 1 mole of $O_{2}$ to give 2 moles of $S O_{3}$
Thus, 1 mole of $S O_{2}$ reacts with $\frac{1}{2}$ mole of $O_{2}$ to give 1 mole of $S O_{3}$
Thus $0.25$ moles of $S O_{2}$ will react with $0.125$ moles of $O_{2}$ to give $0.25$ moles of $S O_{3}$

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Similar questions

2 {S O}_{2} + O_{2} \to 2 {S O}_{3}

With the help of the above reaction equation, determine the maximum number of moles of

S O_{3}

can be produced, if

0.25

moles of sulfur dioxide is mixed with

0.25

moles of oxygen?

Q. At 800 K a reaction mixture contained 0.5 mole of

S O_{2}

. 0.12 mole of

O_{2}

and 5 mole of

S O_{3}

at equilibrium.

K_{c}

for the equilibrium

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

is 833 lit/ mole. If the voiume of the container is 1 litre, calculate how much

O_{2}

is to be added at this equilibrium in order to get 5.2 moles of

S O_{3}

at the same temperature.

Q. One mole of

S O_{3}

was placed in a litre reaction vessel at a certain temperature , the following equilibrium was established,

2 S O_{3} ⇌ 2 S O_{2} + O_{2}

. At equilibrium 0.6 moles of

S O_{2}

were formed. The equilibrium constant of the reaction will be:

Q. One mole of

S O_{3}

was placed in a 1 lit. reaction vessel at a constant temperature. The following equilibrium was established:

2 S O_{3} \Leftrightarrow 2 S O_{2} + O_{2}

. At equilibrium, 0.6 moles of

S O_{2}

were formed. The equilibrium constant of the reaction will be:

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

. Starting with

2

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S O_{2}

and

1

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O_{2}

1

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in acidic medium. Hence, equilibirum constant

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In the reaction 2SO2+O2→2SO3, 0.25 mole of sulfur dioxide is mixed with 0.25 mole of oxygen and allowed to react. What is the maximum number of moles of SO3, that can be produced?

In the reaction $2 S O_{2} + O_{2} \to 2 S O_{3}$ , 0.25 mole of sulfur dioxide is mixed with 0.25 mole of oxygen and allowed to react. What is the maximum number of moles of $S O_{3}$ , that can be produced?