In the reaction-2 X - B 2 H 6- BH 2 X 2- BH 4-X can be-A- NH 3B- CH 3 N H 2C- CH 32 NHD- CH 33 N

The correct options are A NH_3 B CH_3NH_2 C (CH_3)_2NH2NH_3 + B_2H_6 → [BH_2(NH_3)_2]^+[BH_4]^ 2CH_3NH_2 + B_2H_6 → [BH_2(CH_3NH_2)_2]^+[BH_4]^ 2(CH_3)_2NH ...

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Byju's Answer

Standard XII

Chemistry

Other Synthesis Methods

In the reacti...

Question

In the reaction:

$2 X + B_{2} H_{6} \to [B H_{2} X_{2}]^{+} [B H_{4}]^{-}$

X can be:

N H_{3}

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C H_{3} N H_{2}

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(C H_{3})_{2} N H

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(C H_{3})_{3} N

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Solution

The correct options are
A $N H_{3}$
B $C H_{3} N H_{2}$
C $(C H_{3})_{2} N H$
$2 N H_{3} + B_{2} H_{6} \to [B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-}$

$2 C H_{3} N H_{2} + B_{2} H_{6} \to [B H_{2} (C H_{3} N H_{2})_{2}]^{+} [B H_{4}]^{-}$

$2 (C H_{3})_{2} N H + B_{2} H_{6} \to [B H_{2} ((C H_{3})_{2} N H))_{2}]^{+} [B H_{4}]^{-}$

$(C H_{3})_{3} N$ and $B_{2} H_{6}$ forms an adduct.

$(C H_{3})_{3} N + B_{2} H_{6} ⟶ [H_{3} B \leftarrow N (C H_{3})_{3}]$

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Similar questions

$2 X + B_{2} H_{6} ⟶ [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}$ the amine(s) X is/are:

Q. In the reaction

2 X + B_{2} H_{6} \to 2 [B H_{3} X]

the amine (s)

X

is (are):

Q. In the reaction,

2 X + B_{2} H_{6} \to [B H_{2} (X_{2})]^{+} [B H_{4}]^{-}

'X' cannot be ?

Q. In the reaction

2 X + B_{2} H_{6} \to [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}

, the amine(s)

X

is(are):

Q. In the reaction,

2 X + B_{2} H_{6} \to [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}

the amine(s) X is/are

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In the reaction: 2X+B2H6→[BH2X2]+[BH4]− X can be:

The correct options are A NH3 B CH3NH2 C (CH3)2NH2NH3+B2H6→[BH2(NH3)2]+[BH4]− 2CH3NH2+B2H6→[BH2(CH3NH2)2]+[BH4]− 2(CH3)2NH+B2H6→[BH2((CH3)2NH))2]+[BH4]− (CH3)3N and B2H6 forms an adduct. (CH3)3N+B2H6⟶[H3B←N(CH3)3]

In the reaction:

$2 X + B_{2} H_{6} \to [B H_{2} X_{2}]^{+} [B H_{4}]^{-}$

X can be: