Question

In the reaction $3A_2\left(g\right)\rightleftharpoons 2A_3\left(g\right)$, equilibrium is obtained by taking an initial concentration of $A_2$ as (a)mol/liter, if $\alpha$ is the degree of the dissociation then total moles at equilibrium will be

Answer 1

$3A_2=2A_3$

initial: 3a 0

let x mole will be dissociate

$x=a\alpha$

At eqm.$3(a-a\alpha )$ $2a\alpha$

Total no. of moles at equilibrium = $a(1-\alpha )$