Question

In the reaction $3A\to 2B$, rate of reaction $+\frac{d\left[B\right]}{dt}$ is equal to:

• A. $-\frac{1}{3}\frac{d\left[A\right]}{dt}$
• B. $-\frac{2}{3}\frac{d\left[A\right]}{dt}$
• C. $+2\frac{d\left[A\right]}{dt}$
• D. $-\frac{3}{2}\frac{d\left[A\right]}{dt}$

Answer 1

The correct option is B $-\frac{2}{3}\frac{d\left[A\right]}{dt}$

$3A\to 2B$

For the given reaction we can write

rate of reaction: $\frac{-1}{3}\frac{d\left[A\right]}{dt}=\frac{-1}{2}\frac{d\left[B\right]}{dt}$

$\Rightarrow \frac{+d\left[B\right]}{dt}=\frac{-2}{3}\frac{d\left[A\right]}{dt}$