Question

In the reaction ;

$4A+2B+3C\to A_4{B}_2{C}_3$,

what will be the number of moles of product formed, starting from one mole of A, 0.6 mole of B and 0.72 mole of C ?

• A. 0.25
• B. 0.3
• C. 0.24
• D. 2.32

Answer 1

Answer: (C)

0.24

4 mole A react with 2 mole B and 3 mole C

1 mole A will react 0.5 mole B and 0.75 mole C

Hence C is the limiting reagent here.

3 Moles of C form 1 mol product

Therefore 0.72 mole of C will form $\frac{0.72}{3}=0.24mol$ product.