Question

In the reaction,
$4HN{O}_3+P_4{O}_{10}\to 4HP{O}_3+X$; the product $X$ is

• A. $N_2{O}_5$
• B. $N_2{O}_3$
• C. $N{O}_2$
• D. $H_{2}O$

Answer 1

The correct option is A $N_2{O}_5$

$4HN{O}_3+P_4{O}_{10}\to 4HP{O}_3+\underset{\underset{\left(X\right)}{nitrogenpentaoxide}}{N_2{O}_5}$.

So, A is the correct option.