In the reaction 4NO2g-O2g- 2N2O5g- - H -111kJ if N2O5s is formed instead of N2O5g- the -H value in kJ is- - Hsublimation for N2O5-54 kJ mol-1-

The correct option is C 165 Δ H_reaction = Δ H_sublimation+Δ H_formation #160; #160; #160; #160; #160; #160; #160; #160; # ...

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Byju's Answer

Standard XII

Chemistry

Enthalpy

In the reacti...

Question

In the reaction $4 N O_{2_{(g)}} + O_{2}_{(g)} \to 2 N_{2} O_{5_{(g)}}, Δ H = - 111$ kJ if $N_{2} O_{5_{(s)}}$ is formed instead of $N_{2} O_{5_{(g)}}$ , the $Δ$ H value in kJ is:

$[Δ H_{s u b l i m a t i o n}$ for $N_{2} O_{5} = 54$ kJ $m o l^{- 1}]$

- 57

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+ 219

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- 219

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- 165

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Solution

The correct option is C $- 165$
$Δ H_{r e a c t i o n} = Δ H_{s u b l i m a t i o n} + Δ H_{f o r m a t i o n}$
$Δ H_{f} = - 111 - 54$

$= - 165 k J / m o l$

Hence, option D is correct.

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Similar questions

Consider the reaction:

$4 N O_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 k J$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be:

(given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 k J m o l^{- 1}$ )

Consider the reaction:

$4 N O_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 k J$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be: