Question

In the reaction $8Al+{3Fe}_3{O}_4\to {4Al}_2{O}_3+9Fe$, the number of electrons transferred from reductant to oxidant is:

• A. $8$
• B. $4$
• C. $16$
• D. $24$

Answer 1

The correct option is D $24$

$8Al+3{Fe}_3{O}_4⟶4{Al}_2{O}_3+9Fe$

In the above reaction, $Al$ is reductant while $Fe$ is oxidant.

Oxidation no. of $Al$ in transition state $=0$

Oxidation no. of $Al$ in ${Al}_2{O}_3=+3$

$\therefore$ No. of electrons transferred by $1Al$ atom $=3$

$\Rightarrow$ No. of electrons trnsferred by $8Al$ atoms $=8\times 3=24\text{electrons}$

Hence, $24$ electrons are transferred from reductant to oxidant.