In the reaction; $A + 2 B \to 3 C + D$ , which of the following expression does not describe changes in the concentration of various species as a function of time?

{d [C] / d t} = - {3 d [A] / d t}

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{3 d [D] / d t} = {d [C] / d t}

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{3 d [B] / d t} = - {2 d [C] / d t}

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{2 d [B] / d t} = - {d [A] / d t}

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Solution

The correct option is D ${2 d [B] / d t} = - {d [A] / d t}$
$M o l a l i t y = \frac{N o . o f M o l e s o f s o l u t e}{w t (i n k g) o f s o l v e n t}$
$M o l a r i t y = \frac{N o . o f M o l e s}{v o l u m e (i n l i t r e) o f s o l u t i o n}$
$% w e i g h t b y v o l u m e = \frac{w e i g h t o f s l o u t e}{v o l u m e o f s o l u t i o n} \times 100$
$% b y v o l u m e = \frac{v o l u m e o f s o l u t e}{v o l u m e o f s o l u t i o n} \times 100$
$A + 2 B \to 3 C + D$
Rate of reaction can be expressed in the term change in concentration of reactants and products.
Rate of reaction $=$ $- \frac{d [A]}{d t} = - \frac{1}{3} \frac{d [B]}{d t} = \frac{1}{3} \frac{d [C]}{d t} = \frac{d [D]}{d t}$
Hence $,$ the wrong answer is in the Option $(D)$ .

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Similar questions

A + 2 B \to 3 C + D

= \frac{1}{2} \frac{d [C]}{d t} = - \frac{1}{3} \frac{d [D]}{d t} = \frac{1}{4} \frac{d [A]}{d t} = - \frac{d [B]}{d t}

\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})

+ \frac{1}{2} \frac{d [C]}{d t} = - \frac{1}{3} \frac{d [D]}{d t} = + \frac{1}{4} \frac{d [A]}{d t} = - \frac{d [B]}{d t}

\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})

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