Question

In the reaction $A+2B\rightleftharpoons 2C$, if $2$ moles of $A$, $3.0$ moles of $B$ and $2.0$ moles of $C$ are placed in a $2.0l$ falsk and concentration of $C$ is $0.5$ mole/litre. Find the equilibrium constant $K_{\varphi }$ for the reaction.

• A. $0.0089$
• B. $0.147$
• C. $0.05$
• D. $0.025$

Answer 1

The correct option is A $0.0089$

$A+2B\rightleftharpoons 2C$

$232$ Initial moles

$[2-X][3-2X][2-2X]$ Equilibrium moles

But for C equilibrium moles =0.5

$\therefore 2-2x=0.5$

$\therefore X=0.75$

$[2+0.75][3+2X0.75]0.5$ Equilibrium moles

2.75 4.5 0.5 Equilibrium moles

$\frac{2.75}{2}\frac{4.5}{2}\frac{0.5}{2}$ Equilibrium Concentration

K=$\frac{\left(0.5/2\right){}^2}{\left(4.5/2\right){}^2\left(2.75/2\right)}$

$=0.0089$ is the answer.