Question

In the reaction $A^{+}+B\to A+B^{+},$ there is no entropy change. If enthalpy change is $22kJ/mol$, calculate $△G$ for the reaction.

• A. $25kJmo{l}^{-1}$
• B. $28kJmo{l}^{-1}$
• C. $22kJmo{l}^{-1}$
• D. $20kJmo{l}^{-1}$

Answer 1

The correct option is C $22kJmo{l}^{-1}$

For the given reaction, $A^{+}+B\to A+B^{+}$
$△H=22kJ/mol,△S=0$
$\therefore using,△G=△H-T△S$
$△G=22-T\times 0=22kJmo{l}^{-1}$
Hence, $△G$ for the reaction is $22kJmo{l}^{-1}$