Question

In the reaction $A{B}_{\left(g\right)}\rightleftharpoons A_{\left(g\right)}+B_{\left(g\right)}$ at ${30}^{o}C$, $K_p$n for the dissociation equilibrium is $2.56\times {10}^{-2}atm$. If the total pressure at equilibrium is 1 atm, then the percentage dissociation of AB is ?

Answer 1

$AB\left(g\right)\to A\left(g\right)+B\left(g\right)$

$K_p=\frac{{\alpha }^{2}p}{1-{\alpha }^2}=2.56\times {10}^{-2}$ atm

$=\frac{{\alpha }^2\times 1atm}{1-{\alpha }^2}=2.56\times {10}^{-}$ 2atm

$\alpha =0.16$

$=16$