Question

In the reaction : $A{l}_2(S{O}_4{)}_3\cdot 18H_{2}O\underset{-18H_{2}O}{\overset{heat}{\to }}A\stackrel{{800}^{o}C}{\to }B+C$. The product A, B and C are respectively :

• A. $A{l}_2(S{O}_4{)}_3,A{l}_2{O}_3,S{O}_3$
• B. $A{l}_2{O}_3,A{l}_2(S{O}_4{)}_3,S{O}_3$
• C. $A{l}_{2}S{O}_4,A{l}_2{O}_3,S{O}_3$
• D. $A{l}_2(S{O}_4{)}_3,A{l}_2{O}_3,S{O}_2$

Answer 1

The correct option is A $A{l}_2(S{O}_4{)}_3,A{l}_2{O}_3,S{O}_3$

$A{l}_2(S{O}_4{)}_3\cdot 18H_{2}O\underset{-18H_{2}O}{\overset{heat}{\to }}A{l}_2(S_4{)}_3\stackrel{{800}^{o}C}{\to }A{l}_2{O}_3+SO3$
Hence option A is correct.