Question

In the reaction below, the product would be:

$C{H}_3-CH=CH-C{H}_3+O{H}_2\stackrel{H_3\stackrel{+}{O}}{\to }C{H}_{3}C{H}_2\stackrel{OH}{\stackrel{|}{C}H}C{H}_3$

• A. a mixture of diastereomers
• B. optically active
• C. un resolvale
• D. a racemate

Answer 1

The correct option is D a racemate

In the given reaction, the product would be a racemate.
$2-butene$ is protonated to form carbocation intermediate. This is followed by the attack of a water molecule and deprotonation. Water can attack to give an equal proportion of two enantiomers of $2-butanol$. Hence, a racemic mixture is obtained.