Question

# In the reaction between NO and H2 the following data are obtainedExperiment 1 : PH2 = constant (mm of Hg)359300152−PH2dt1.501.030.25Experiment 2: PNO= constantPH2 (mm of Hg)289205147−PH2dt1.601.100.79The orders with respect of H2 and NO are:

A
1 with respect to NO and 2 with respect to H2
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B
2 with respect to NO and 1 with respect to H2
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C
1 with respect to NO and 3 with respect to H2
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D
2 with respect to NO and 2 with respect to H2
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Solution

## The correct option is B 2 with respect to NO and 1 with respect to H2Let us consider the orders are α and β with respect to NO and H2 respectively.Expt 1.−PNodt=K1(PNo)α⇒359152=(1.50.25)α⇒2.36=(6)α⇒2.36=(2.36)2⇒α=2Expt 2−PH2dt=K2.(pH2)βnow, 289147=(1.60.79)β⇒1.97=(2.02)β⇒β≈1∴ The orders 1 with H2 and 2 with respect to NO.

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