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Question

In the reaction between NO and H2 the following data are obtained
Experiment 1 : PH2 = constant

(mm of Hg)359300152
PH2dt1.501.030.25
Experiment 2: PNO= constant
PH2 (mm of Hg)289205147
PH2dt1.601.100.79
The orders with respect of H2 and NO are:

A
1 with respect to NO and 2 with respect to H2
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B
2 with respect to NO and 1 with respect to H2
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C
1 with respect to NO and 3 with respect to H2
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D
2 with respect to NO and 2 with respect to H2
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Solution

The correct option is B 2 with respect to NO and 1 with respect to H2
Let us consider the orders are α and β with respect to NO and H2 respectively.
Expt 1.
PNodt=K1(PNo)α
359152=(1.50.25)α
2.36=(6)α2.36=(2.36)2α=2
Expt 2
PH2dt=K2.(pH2)β
now, 289147=(1.60.79)β
1.97=(2.02)ββ1
The orders 1 with H2 and 2 with respect to NO.

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