In the reaction between zinc and iodine, zinc iodide is formed. What is being oxidized?

Zinc ions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Iodide ions

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Zinc atom

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Iodine

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Zinc atom
$Z n + I_{2} \to Z n I_{2}$
$Z n \to Z n^{2 +} + 2 e^{-}$ (loss of electron oxidation)
$I + e^{-} \to I^{-}$ (gain of electron reduction)

Suggest Corrections

Similar questions

Q. Equal weights of zinc and iodine react together and the iodine is completely converted to

Z n I_{2}

. What fraction by weight of the original zinc remains unreacted? (

Z n = 65, I = 127

g/mol)

1) zinc carbonate= zinc oxide+ carbon dioxide

2) potassium bromide+ barium iodide = potassium iodide + barium bromide

Balance the equations

Q. In a reaction of acidified hydrogen peroxide with potassium iodide, the concentration of iodine formed rises from

0

10^{- 5}

m o l

{d m}^{- 3}

10

seconds. What is the rate of reaction?

Q. Zinc upon reaction with steam forms zinc oxide and .

Write the balanced chemical equation for the following and identify the type of reaction in each case –
$(A) P o t a s s i u m b r o m i d e (a q) + B a r i u m i o d i d e (a q) \to P o t a s s i u m i o d i d e (a q) + B a r i u m b r o m i d e (s)$

$(B) Z i n c c a r b o n a t e (s) \to Z i n c o x i d e (s) + C a r b o n d i o x i d e (g)$

Join BYJU'S Learning Program

In the reaction between zinc and iodine, zinc iodide is formed. What is being oxidized?

The correct option is A Zinc atomZn+I2→ZnI2Zn→Zn2++2e− (loss of electron oxidation)I+e−→I−(gain of electron reduction)

The correct option is A Zinc atom
$Z n + I_{2} \to Z n I_{2}$
$Z n \to Z n^{2 +} + 2 e^{-}$ (loss of electron oxidation)
$I + e^{-} \to I^{-}$ (gain of electron reduction)