Question

in the reaction $C_2{H}_5{OH}_2{H}_5+CO\begin{array}{c}{BF}_{3500atms}\\ ⟶\\ {150}^{\circ }C\end{array}X$. What is $X$?

• A. $Diethylcarbonate$
• B. $Ethylcarbonate$
• C. $Diethylperoxide$
• D. $Ethylpropionate$

Answer 1

The correct option is D $Ethylpropionate$

Option D is the correct answer.
The general reaction between ether and CO is
$R-O-R+CO\underset{150°C}{\overset{B{F}_3,500atm}{\to }}R-CO-O-R$
By that logic, the given reaction should yield
$C_2{H}_5-O-C_2{H}_5+CO\underset{150°C}{\overset{B{F}_3,500atm}{\to }}{C}_2{H}_{5}CO-O-C_2{H}_5$ i.e. Ethyl propionate.