In the reaction C 2 O 42- MnO 4- H - Mn 2- CO 2- H 2 O which is the reducing agent-A- C 2 O 42-B- MnO 4-C- Mn 2-D- H -

The correct option is A C_2O_4^2 C_2O_4^2 +MnO_4^ +H^+→ Mn^2++CO_2+H_2O C_2O_4^2 2x + 4×( 2) = 2 2x = 2 + 8 2x = 6 x = +3 whereas in the product side Oxida ...

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Byju's Answer

Standard IX

Chemistry

Calculating Oxidation Number

In the reacti...

Question

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?

$C_{2} O_{4}^{2 -}$

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$M n O_{4}^{-}$

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$M n^{2 +}$

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$H^{+}$

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Solution

The correct option is A
$C_{2} O_{4}^{2 -}$

$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$

$C_{2} O_{4}^{2 -}$

$2 x + 4 \times (- 2) = - 2$

$2 x = - 2 + 8$

$2 x = 6$

$x = + 3$

whereas in the product side Oxidation number of carbon = +4

That shows that it has donated one electron, thereby oxidizing others.

In this reaction $C_{2} O_{4}^{2 -}$ act as a reducing agent.

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Similar questions

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

Q. In the reaction

C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

the reductant is

M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to C O_{2} + H_{2} O + M n^{2 +}

The correct coefficients of

M n O_{4}^{-}, C_{2} O_{4}^{2 -}

and

H^{+}

are respectively :

Q. Coefficients of

M n O_{4}^{2 -}, C_{2} O_{4}^{2 -}

and

H^{+}

in the balanced reaction.

M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

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In the reaction C2O2−4+MnO−4+H+→Mn2++CO2+H2O which is the reducing agent?

The correct option is A C2O2−4 C2O2−4+MnO−4+H+→Mn2++CO2+H2O C2O2−4 2x + 4×(−2)=−2 2x=−2+8 2x=6 x=+3 whereas in the product side Oxidation number of carbon = +4 That shows that it has donated one electron, thereby oxidizing others. In this reaction C2O2−4 act as a reducing agent.

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?