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Raoult's Law

In the reacti...

Question

In the reaction $C (s) + C O_{2} (g) ⇌ 2 C O (g)$ , the equilibrium pressure is $12 a t m$ . If $50 %$ of $C O_{2}$ reacts then $K_{p}$ will be:

12 atm

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16 atm

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20 atm

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24 atm

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Solution

The correct option is A 16 atm
$C (s) + C O_{2} (g) ⇌ 2 C O (g)$
0.5 1
$K_{P} = \frac{p_{C O}^{2}}{p_{C O_{2}}}$
$K_{P} = \frac{(12 \times (1 / 1.5))^{2}}{12 \times (0.5 / 1.5)} = 16$

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