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Uses of Slaked Lime

In the reacti...

Question

In the reaction:
$C a C O_{3} + H_{2} S O_{4} \to C a S O_{4} + H_{2} O + C O_{2}$
Calculate the amount (in g) of $H_{2} S O_{4}$ required to decompose $10 g C a C O_{3}$

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Solution

According to the reaction, 1 mol of $C a C O_{3}$ reacts with 1 mol of $H_{2} S O_{4}$
i.e., $100 g$ of $C a C O_{3}$ react with $98 g$ of $H_{2} S O_{4}$
So, $10 g$ of $C a C O_{3}$ will require $(\frac{98}{100} \times 10) = 9.8 g$ of $H_{2} S O_{4}$

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