Question

In the reaction ${CH}_{3}C\equiv \stackrel{\oplus }{CNa}+{\left({CH}_3\right)}_{2}CHCl⟶$ the product formed is:

• A. $4$-Methyl-$2$-pentyne only
• B. Propyne
• C. Propyne and propylene
• D. Mixture of propene, propyne, and $4$-methyl-$2$-pentyne

Answer 1

The correct option is D Mixture of propene, propyne, and $4$-methyl-$2$-pentyne

Hence the answer is $\left(D\right)$