In the reaction-CH3COOH A B C- the product C is-

CH_3COOH LiAH_4→ CH_3CH_2OH PCl_5→ CH_3CH_2Cl alc. KOH→(ethylene)H_2C = CH_2 ...

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In the reacti...

Question

In the reaction,
$C H_{3} C O O H L i A l H_{4} - --- \to A P C l_{5} - -- \to B A l c . K O H - ----- \to C,$ the product C is:

Ethylene

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Acetyl chloride

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Acetaldehyde

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Acetylene

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C H_{3} C O O H L i A l H_{4} - --- \to A P C l_{5} - -- \to B A l c . K O H - ----- \to C,

{C H}_{3} C O O H C a {C O}_{3} - --- \to A H e a t - -- \to B {N H}_{2} O H - ---- \to C

^{'} C^{'}

C H_{3} C O O H C a C O_{3} - --- \to A H e a t - -- \to B N H_{2} O H - ---- \to C

C H_{3} C O O H N H_{3} - -- \to A Δ - \to B P_{2} O_{5} - -- \to C

{C H}_{3} C O O H C a {(O H)}_{2} - ---- \to A C a {(O O C H)}_{2} - ------- \to Δ B {N H}_{2} O H - ---- \to C

C

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