Question

In the reaction, $C{H}_3-\stackrel{\stackrel{O}{||}}{\underset{\ast }{C}}-N{H}_2$ $\stackrel{P_2{O}_5}{\underset{\Delta }{\to }}C{H}_3-\underset{\ast }{C}\equiv N$, the hybridization state of marked carbon atom changes from?

• A. $s{p}^2$ to $sp$
• B. $s{p}^3$ to $sp$
• C. $s{p}^3$ to $s{p}^2$
• D. $s{p}^2$ to $s{p}^3$

Answer 1

Answer: (A)

$s{p}^2$ to $sp$

The reactant side Carbon is in $s{p}^2$ state as it has 3 sigma bonds. The product side carbon contains only 2 sigma bond and hence has $sp$ hybridization.
Option A is correct.