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Question

In the reaction, CH3COOHLiAlH4−−−−→APCl5−−−→BAlc.KOH−−−−−−→C the final product is:

A
acetaldehyde
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B
acetylene
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C
ethylene
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D
acetylchloride
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Solution

The correct option is C ethylene
In the given reaction the final product is ethylene.

CH3COOHLiAlH4−−−CH3CH2OH APCl5−−CH3CH2Cl B Alc.KOH−−−−−CH2=CH2 C

Lithium aluminum hydride reduces acetic acid to ethyl alcohol. PCl5 converts alcohol to alkyl chloride.

The final step is dehydrohalogenation to form alkene.

Option C is correct.

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