In the reaction, $C O_{3}^{2 -} + H_{2} O (I) = H C O_{3}^{-} (a q) + O H^{-} (a q)$ water is a:

bronsted acid

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bronsted base

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conjugate acid

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conjugate base

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Solution

The correct option is A bronsted acid
In the given equation water acts as a Bronsted acid since it donates a proton to carbonate ion

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Similar questions

H C O_{3}^{-} (a q .) + O H^{-} (a q .) \to C O_{3}^{2} (a q .) + H_{2} O

C O_{3}^{2 -} + H_{2} O (l) = H C O_{3}^{-} + O H^{-} (a q)

H C O_{3}^{-} + H_{2} O \to C O_{3}^{2 -} + H_{3} O^{+}

H C O_{3}^{-}

H C O_{3}^{-}

H C O_{3}^{-} + H_{2} O ⇌ H_{3} O^{+} + C O_{3}^{2 -}

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