Question

In the reaction, $Cr{O}_5+SnC{l}_2\to Cr{O}_4^{2-}+SnC{l}_4$, the element undergoing oxidation and reduction respectively, are________.

• A. Cr, Sn
• B. Sn, Cr
• C. Sn, O
• D. Cl, C

Answer 1

The correct option is C Sn, O

In $Cr{O}_5$,$Cr$ has +6 oxidation state and in ${Cr{O}_4}^{2-}$ it has +6 oxidation state so it has neither undergo oxidation nor reduction.In $Cr{O}_5$,$O$ has $\frac{6}{5}$ oxidation state and in ${Cr{O}_4}^{2-}$ it has -2 oxidation state so it undergo reduction.

In $SnC{l}_2$,$Sn$ has +2 oxidation state and in ${SnC{l}_4}^{}$ it has +4 oxidation state so it has undergo oxidation.