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Question

In the reaction

CS2(l) + 3O2(g) CO2(g) + 2SO2(g) ΔH = 265 kcal

The enthalpies of formation of CO2 and SO2 are both negative and are in the ratio 4 : 3. The enthalpy of formation of CS2 is +26 kcal/mol. Calculate the enthalpy of formation of SO2.


A

−90 kcal/mol

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B

−52 kcal/mol

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C

−78 kcal/mol

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D

−71.7 kcal/mol

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Solution

The correct option is D

−71.7 kcal/mol


CS2(l) + 3O2(g) CO2(g) + 2SO2(g)

ΔH = 256 Kcal

Let ΔHr(CO2,g) = 4x and ΔHr(SO2,g) = 3x

ΔHreaction = ΔHf(CO2,g) + 2ΔΔf(SO2,g) ΔHf(CS2I)

265 = 4x 6x 26

x = +23.9

Δf(SO2,g) = 3x = 71.7 Kcal/mol


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