In the reaction CS2(l)+3O2(g)→CO2(g)+2SO2(g)△H=−265kcal
The enthalpies of formation of CO2 and SO2 are both negative and are in the ratio 4 : 3. The enthalpy of formation of CS2 is + 26 kcal/mol. Calculate the enthalpy of formation of SO2.
A
- 90 kcal/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
-52 kcal/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-78 kcal/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
-71.7 kcal/mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D -71.7 kcal/mol CS2(l)+3O2(g)→CO2(g)+2SO2(g)△H=−265kcal
Let △Hf(CO2,g)=−4xand△Hf(SO2,g)=−3x △Hreaction=△Hf(CO2,g)+2△Hf(SO2,g)−△Hf(CS2,l) −265=−4x−6x−26 x=+23.9 ∴△Hf(SO2,g)=−3x=−71.7kcal/mol.