In the reaction- Cu - H 2 SO 4- CuSO 4- H 2 O - SO 2A- H -is an oxidation agentB- SO 42- is an oxidising agentC- Both a and b correctD- None of these

The correct option is B SO_4^2 is an oxidising agentThe balance equation is : 0Cu +2H_2+6SO_4 →+2CuSO_4 +2H_2O + +4SO_2 Cu is oxidised from 0 oxidation state ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Redox Reactions

In the reacti...

Question

In the reaction,
$C u + H_{2} S O_{4} \to C u S O_{4} + H_{2} O + S O_{2}$

H^{+}

is an oxidation agent

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{4}^{2 -}

is an oxidising agent

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Both (a) and (b) correct

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $S O_{4}^{2 -}$ is an oxidising agent
The balance equation is :
$0 C u + 2 H_{2} + 6 S O_{4} \to + 2 C u S O_{4} + 2 H_{2} O + + 4 S O_{2}$

Cu is oxidised from 0 oxidation state to +2 oxidation satate by $S O_{4}^{2 -}$ . Hence $S O_{4}^{2 -}$ is an oxidising agent.

Suggest Corrections

Similar questions

Q. In a reaction,

2 A g + 2 H_{2} S O_{4} \to A g_{2} S O_{4} + H_{2} O + S O_{2}

H_{2} S O_{4}

acts as:

Q. In

C + H_{2} O ⟶ C O + H_{2}, H_{2} O

acts as a:

Q. In

C + H_{2} O ⟶ C O + H_{2}, H_{2} O

acts as

Q. In

C + H_{2} O \to C O + H_{2}

H_{2} O

acts as

CuO + H₂SO₄ → CuSO₄ + H₂O is an example of which property of the sulphuric acid?

Join BYJU'S Learning Program

Explore more

Redox Reactions

Standard XII Chemistry

Join BYJU'S Learning Program

In the reaction, Cu+H2SO4→CuSO4+H2O+SO2

The correct option is B SO2−4 is an oxidising agentThe balance equation is : 0Cu+2H2+6SO4→+2CuSO4+2H2O++4SO2 Cu is oxidised from 0 oxidation state to +2 oxidation satate by SO2−4. Hence SO2−4 is an oxidising agent.

In the reaction,
$C u + H_{2} S O_{4} \to C u S O_{4} + H_{2} O + S O_{2}$

The correct option is B $S O_{4}^{2 -}$ is an oxidising agent
The balance equation is :
$0 C u + 2 H_{2} + 6 S O_{4} \to + 2 C u S O_{4} + 2 H_{2} O + + 4 S O_{2}$

Cu is oxidised from 0 oxidation state to +2 oxidation satate by $S O_{4}^{2 -}$ . Hence $S O_{4}^{2 -}$ is an oxidising agent.