Question

In the reaction :-
$CuS{O}_4\cdot 3H_{2}O\left(s\right)\rightleftharpoons 2CuS{O}_4\cdot H_{2}O\left(s\right)+2H_{2}O\left(v\right)$,

Dissociation pressure is $7\times {10}^{-3}$ atm at $25$ and $\Delta H=2700cal$. If the dissociation pressure at $127$ is $X\times {10}^{-3}$ atm, then $100X$ is__________.

Answer 1

$log\frac{K_2}{K_1}=\frac{\Delta H}{2.303R}(\frac{1}{T_1}-\frac{1}{T_2)})$
Substitute values in the above expression
$log\frac{K_2}{K_1}=\frac{2700}{2.303\times 2}(\frac{1}{298}-\frac{1}{400)})$
$log\frac{K_2}{K_1}=0.5$
$\frac{K_2}{K_1}=3.16$
$(\frac{P}{7\times {10}^{-3}}{)}^2=3.16$
$P=12.46\times {10}^{-3}=x\times {10}^{-3}$
$x=12.46$
$100x=1246$