1
Question
In the reaction CuSO4⋅3H2O(s)⇌CuSO4H2O(s)+2H2O(v), the dissociation pressure is 7×10−3atm at 25∘C and △H∘=2700 cal. What will be the dissociation pressure at 127∘C?
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Solution
CuSO4+3H2O⇌CuSO4.H2O+2H2OGiven vapour pressure =7×10−3So, K1P=(7×10−3)2=49×10−6 at 250CSo at 1270C Let it bI KP2In(KP249×10−6)=−(27002)(1400−1298)
KP2=1.556×10−4
KP2=(P2)2
P2=√1.556×10−4
P1270C=1.24×10−2atm
Given vapour pressure =7×10−3
So, K1P=(7×10−3)2=49×10−6 at 250C
So at 1270C Let it bI KP2
In(KP249×10−6)=−(27002)(1400−1298)
KP2=1.556×10−4
KP2=(P2)2
P2=√1.556×10−4
P1270C=1.24×10−2atm
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