Question

In the reaction $3A⟶2B$, rate of reaction $+\frac{d\left(B\right)}{dt}$ is equal to

• A. $-\frac{1}{3}\frac{d\left[A\right]}{dt}$
• B. $-\frac{2}{3}\frac{d\left[A\right]}{dt}$
• C. $+\frac{2d\left[A\right]}{dt}$
• D. $-\frac{3}{2}\frac{d\left[A\right]}{dt}$

Answer 1

The correct option is B $-\frac{2}{3}\frac{d\left[A\right]}{dt}$

For the reaction,
$3A⟶2B$
$=-\frac{1}{3}\frac{d\left[A\right]}{dt}=+\frac{1}{2}\frac{d\left[B\right]}{dt}$
$+\frac{d\left[B\right]}{dt}=-\frac{2}{3}\frac{d\left[A\right]}{dt}$