Question

In the reaction, $F_{3}C-CH=CHCl\stackrel{HCl}{\to }$ the major product is:

• A. $F_{3}C-CHCl-C{H}_{2}Cl$
• B. $F_{3}C-C{H}_2-CHC{l}_2$
• C. $F_{3}C-C{H}_2-C{H}_{2}Cl$
• D. $F_{2}C=\underset{\underset{Cl}{|}}{C}-C{H}_{2}Cl$

Answer 1

The correct option is B $F_{3}C-C{H}_2-CHC{l}_2$

$C{F}_3-CH=CH-Cl\stackrel{HCl}{\to }C{F}_3-C{H}_2-C\stackrel{\oplus }{H}-Cl$

$\downarrow C{l}^{-}$

$C{F}_3-C{H}_2-CHC{L}_2$