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Modern Periodic Table

In the reacti...

Question

In the reaction given below :
$2 F e {C l}_{3} + H_{2} S ⟶ 2 F e {C l}_{2} + 2 H C l + S$

F e {C l}_{3}

acts as an oxidising agent

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both

H_{2} S

and

F e {C l}_{3}

are oxidised

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F e {C l}_{3}

is oxidised while

H_{2} S

is reduced

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H_{2} S

acts as an oxidising agent

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Solution

The correct option is A $F e {C l}_{3}$ acts as an oxidising agent
The oxidation number of iron changes from +3 to +2. Hence, $F e C l_{3}$ is reduced and acts as oxidizing agent.
The oxidation number of S changes from -2 to 0. Hence, $H_{2} S$ is oxidized and acts as reducing agent. Thus, only option A is correct.

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