In the reaction given below, at constant pressure, the work done by system on surrounding is?
$H_{2} O (g) \to H_{2} O (l)$

positive

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negative

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no work is done

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positive at temperatures above critical temperature

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Solution

The correct option is B positive
The volume of liquid is greater than vapor.
Hence, change in volume is positive
Therefore, Work done W= $P (V_{l} - V_{g}) > 0$

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