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Oxidation and Reduction

In the reacti...

Question

In the reaction given below:
$S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O$
The substance which is oxidised is :

H_{2} S

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S O_{2}

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S

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H_{2} O

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Solution

The correct option is A $H_{2} S$
The half cell reactions are given below:
$S^{2 -} ⟶ S + 2 e^{-}$ (Oxidation)
Therefore, $H_{2} S$ is oxidised.
$4 e^{-} + S O_{2} ⟶ S$ (Reduction)
$S O_{2}$ is reduced.

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