Question

In the reaction given below, the product $X$ is:

$4HN{O}_3+P_4{O}_{10}\to 4HP{O}_3+X$

• A. $N_2{O}_5$
• B. $N_2{O}_3$
• C. $N{O}_2$
• D. $H_{2}O$

Answer 1

Answer: (A)

$N_2{O}_5$

The reaction is as follows:
$4HN{O}_3+P_4{O}_{10}\to 4HP{O}_3+2N_2{O}_5$

Hence, the product is $N_2{O}_5$.