Question

In the reaction gives below,
$R-Cl\stackrel{\left(i\right)KCN,\left(ii\right)LiAl{H}_4}{\to }ProductA$
$R-Cl\stackrel{\left(i\right)AgCN,\left(ii\right)LiAl{H}_4}{\to }ProductB$
The compounds $A$ and $B$ are:

• A. chain isomers
• B. position isomers
• C. functional isomers
• D. metamers

Answer 1

Answer: (C)

functional isomers

$R-Cl\underset{}{\overset{KCN/LiAl{H}_4}{\to }}RCN⟶RC{H}_{2}N{H}_2$

$R-Cl\underset{}{\overset{AgCN/LiAl{H}_4}{\to }}RCN⟶R-NH-C{H}_2$

Hence the product are functional isomers.